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Question Number 26364 by d.monhbayr@gmail.com last updated on 24/Dec/17
$${y}={x}^{\mathrm{2}} \left({x}−\mathrm{1}\right)^{\mathrm{2}} \\ $$$${min}=?\:\:\:{max}=? \\ $$$${help}\:{pls} \\ $$
Commented by mrW1 last updated on 24/Dec/17
$${there}\:{is}\:{no}\:{max},\:{since}\:{y}\rightarrow\infty\:{when}\:{x}\rightarrow\pm\infty. \\ $$$${y}={x}^{\mathrm{2}} \left({x}−\mathrm{1}\right)^{\mathrm{2}} \geqslant\mathrm{0} \\ $$$$\Rightarrow{min}=\mathrm{0} \\ $$