Question Number 21280 by [email protected] last updated on 18/Sep/17
$${cosec}^{\mathrm{2}} \mathrm{67}^{\mathrm{0}} −{tan}^{\mathrm{2}} \mathrm{23}^{\mathrm{0}} = \\ $$
Answered by $@ty@m last updated on 18/Sep/17
$$\mathrm{1} \\ $$
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Question Number 21280 by [email protected] last updated on 18/Sep/17 | ||
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$${cosec}^{\mathrm{2}} \mathrm{67}^{\mathrm{0}} −{tan}^{\mathrm{2}} \mathrm{23}^{\mathrm{0}} = \\ $$ | ||
Answered by $@ty@m last updated on 18/Sep/17 | ||
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$$\mathrm{1} \\ $$ | ||