Previous in Probability and Statistics Next in Probability and Statistics
Question Number 208812 by Adeyemi889 last updated on 23/Jun/24
Answered by mr W last updated on 23/Jun/24
$$\left({a}\right) \\ $$$${p}=\frac{{C}_{\mathrm{2}} ^{\mathrm{4}} +{C}_{\mathrm{2}} ^{\mathrm{12}} +{C}_{\mathrm{2}} ^{\mathrm{8}} }{{C}_{\mathrm{2}} ^{\mathrm{24}} }=\frac{\mathrm{6}+\mathrm{66}+\mathrm{28}}{\mathrm{276}}=\mathrm{0}.\mathrm{362} \\ $$$$\left({b}\right) \\ $$$${p}=\frac{\mathrm{4}×\mathrm{12}+\mathrm{4}×\mathrm{8}+\mathrm{12}×\mathrm{8}}{\mathrm{276}}=\mathrm{0}.\mathrm{638} \\ $$$$\left({c}\right) \\ $$$${p}=\frac{\mathrm{4}×\mathrm{12}}{\mathrm{276}}=\mathrm{0}.\mathrm{174} \\ $$