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Question Number 208608 by Tawa11 last updated on 18/Jun/24

Answered by mr W last updated on 18/Jun/24

R^2 =((a/2))^2 +((a/2)+b)^2 ⇒R=(√((a^2 /2)+ab+b^2 ))

$${R}^{\mathrm{2}} =\left(\frac{{a}}{\mathrm{2}}\right)^{\mathrm{2}} +\left(\frac{{a}}{\mathrm{2}}+{b}\right)^{\mathrm{2}} \\ $$$$\Rightarrow{R}=\sqrt{\frac{{a}^{\mathrm{2}} }{\mathrm{2}}+{ab}+{b}^{\mathrm{2}} } \\ $$

Commented by Tawa11 last updated on 18/Jun/24

Please sir, Show me the connection lines you used. Thanks sir

$$\mathrm{Please}\:\mathrm{sir}, \\ $$$$\mathrm{Show}\:\mathrm{me}\:\mathrm{the}\:\mathrm{connection}\:\mathrm{lines}\:\mathrm{you}\:\mathrm{used}. \\ $$$$\mathrm{Thanks}\:\mathrm{sir} \\ $$

Commented by mr W last updated on 18/Jun/24

Commented by Tawa11 last updated on 18/Jun/24

God bless you sir. I really appreciate

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate} \\ $$

Answered by efronzo1 last updated on 19/Jun/24

(√2) = (√((a+b)^2 +b^2 )) = (√((a^2 +2ab+2b^2 )/2))

$$\:\: \sqrt{\mathrm{2}}\:=\:\sqrt{\left({a}+{b}\right)^{\mathrm{2}} +{b}^{\mathrm{2}} } \\ $$$$\:\: =\:\sqrt{\frac{{a}^{\mathrm{2}} +\mathrm{2}{ab}+\mathrm{2}{b}^{\mathrm{2}} }{\mathrm{2}}}\: \\ $$

Commented by Tawa11 last updated on 19/Jun/24

Thanks sir

$$\mathrm{Thanks}\:\mathrm{sir} \\ $$

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