Question and Answers Forum

All Questions      Topic List

Trigonometry Questions

Previous in All Question      Next in All Question      

Previous in Trigonometry      Next in Trigonometry      

Question Number 200761 by a.lgnaoui last updated on 23/Nov/23

Determiner  r  et  R  (voir figure )   Sachant aue:∡C=120  :AB=12

$$\boldsymbol{\mathrm{Determiner}}\:\:\boldsymbol{\mathrm{r}}\:\:\mathrm{et}\:\:\boldsymbol{\mathrm{R}}\:\:\left({voir}\:{figure}\:\right) \\ $$$$\:\mathrm{Sachant}\:\mathrm{aue}:\measuredangle\boldsymbol{\mathrm{C}}=\mathrm{120}\:\::\boldsymbol{{AB}}=\mathrm{12} \\ $$

Commented by a.lgnaoui last updated on 23/Nov/23

Commented by mr W last updated on 23/Nov/23

do you mean “r=? and R=?” or  “r+R=?” ?

$${do}\:{you}\:{mean}\:``{r}=?\:{and}\:{R}=?''\:{or} \\ $$$$``{r}+{R}=?''\:? \\ $$

Commented by a.lgnaoui last updated on 23/Nov/23

find r  and R

$$\mathrm{find}\:\boldsymbol{\mathrm{r}}\:\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{R}} \\ $$

Commented by a.lgnaoui last updated on 23/Nov/23

(A and B are the centre of circle :radius r)

$$\left(\boldsymbol{\mathrm{A}}\:\mathrm{and}\:\boldsymbol{\mathrm{B}}\:\mathrm{are}\:\mathrm{the}\:\mathrm{centre}\:\mathrm{of}\:\mathrm{circle}\::\mathrm{radius}\:\boldsymbol{\mathrm{r}}\right)\: \\ $$

Commented by mr W last updated on 23/Nov/23

i think you can not determine r and  R. you can only determine the sum  of r and R, i.e. r+R.

$${i}\:{think}\:{you}\:{can}\:{not}\:{determine}\:{r}\:{and} \\ $$$${R}.\:{you}\:{can}\:{only}\:{determine}\:{the}\:{sum} \\ $$$${of}\:{r}\:{and}\:{R},\:{i}.{e}.\:{r}+{R}. \\ $$

Answered by mr W last updated on 23/Nov/23

AC=r+R−5  BC=r+R−3  say s=r+R  (s−5)^2 +(s−3)^2 +(s−5)(s−3)=12^2   3s^2 −24s−95=0  s=((12+(√(429)))/3)≈10.9

$${AC}={r}+{R}−\mathrm{5} \\ $$$${BC}={r}+{R}−\mathrm{3} \\ $$$${say}\:{s}={r}+{R} \\ $$$$\left({s}−\mathrm{5}\right)^{\mathrm{2}} +\left({s}−\mathrm{3}\right)^{\mathrm{2}} +\left({s}−\mathrm{5}\right)\left({s}−\mathrm{3}\right)=\mathrm{12}^{\mathrm{2}} \\ $$$$\mathrm{3}{s}^{\mathrm{2}} −\mathrm{24}{s}−\mathrm{95}=\mathrm{0} \\ $$$${s}=\frac{\mathrm{12}+\sqrt{\mathrm{429}}}{\mathrm{3}}\approx\mathrm{10}.\mathrm{9} \\ $$

Commented by a.lgnaoui last updated on 26/Nov/23

thanks

$$\mathrm{thanks} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com