Question Number 165867 by Bagus1003 last updated on 09/Feb/22 | ||
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$$\mathrm{2}\:×\:{x}!\:=\:\frac{\mathrm{96}}{\mathrm{2}\:+\:\mathrm{1}\:−\:\mathrm{1}} \\ $$$${How}\:{much}\:{the}\:{x}\:{is}? \\ $$ | ||
Commented by MJS_new last updated on 09/Feb/22 | ||
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$$\mathrm{2}+\mathrm{1}−\mathrm{1}\:...\:\mathrm{this}\:\mathrm{is}\:{much}\:\mathrm{too}\:\mathrm{hard}!\:\mathrm{please},\:\mathrm{post} \\ $$$$\mathrm{some}\:\mathrm{easier}\:\mathrm{questions} \\ $$ | ||
Answered by alephzero last updated on 09/Feb/22 | ||
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$$\mathrm{2}{x}!\:=\:\frac{\mathrm{96}}{\mathrm{2}} \\ $$$$\Rightarrow\:\mathrm{2}{x}!\:=\:\mathrm{48} \\ $$$$\Rightarrow\:{x}!\:=\:\mathrm{24} \\ $$$$\Rightarrow\:{x}\:=\:\mathrm{4} \\ $$ | ||
Commented by Bagus1003 last updated on 10/Feb/22 | ||
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$${thanks} \\ $$ | ||