Question Number 38562 by shakirhsp@gmail.com last updated on 27/Jun/18 | ||
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$$\left(\sqrt{\mathrm{2}}\:+{i}\right)\left(\mathrm{1}−\sqrt{\mathrm{2}{i}}\:\right) \\ $$ | ||
Answered by MJS last updated on 27/Jun/18 | ||
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$$\left(\sqrt{\mathrm{2}}+\mathrm{i}\right)\left(\mathrm{1}−\sqrt{\mathrm{2i}}\right)=\left(\sqrt{\mathrm{2}}+\mathrm{i}\right)\left(\mathrm{1}−\left(\mathrm{1}+\mathrm{i}\right)\right)= \\ $$$$=\left(\sqrt{\mathrm{2}}+\mathrm{i}\right)\left(−\mathrm{i}\right)=\mathrm{1}−\mathrm{i}\sqrt{\mathrm{2}} \\ $$$$\left(\sqrt{\mathrm{2}}+\mathrm{i}\right)\left(\mathrm{1}−\sqrt{\mathrm{2}}\mathrm{i}\right)=\sqrt{\mathrm{2}}−\mathrm{2i}+\mathrm{i}+\sqrt{\mathrm{2}}=\mathrm{2}\sqrt{\mathrm{2}}−\mathrm{i} \\ $$ | ||
Commented by shakirhsp@gmail.com last updated on 04/Jul/18 | ||
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$$ \\ $$$$ \\ $$$$ \\ $$$$\mathrm{thanks}\:\mathrm{brother} \\ $$$$ \\ $$ | ||