Question Number 145279 by mathdanisur last updated on 03/Jul/21
$$\mathrm{2}^{\boldsymbol{{a}}!} \:+\:\mathrm{2}^{\boldsymbol{{b}}!} \:+\:\mathrm{2}^{\boldsymbol{{c}}!} \:=\:\boldsymbol{{x}} \\ $$$${Find}\:{natural}\:{numbers}\:\boldsymbol{{a}};\boldsymbol{{b}};\boldsymbol{{c}}\:{such} \\ $$$${that}\:{the}\:{number}\:``\boldsymbol{{x}}''\:{is}\:{a}\:{cube}\:{of} \\ $$$${any}\:{number}. \\ $$
Answered by SinNombre last updated on 03/Jul/21
$${hablas}\:{espaniol}\:{porfa} \\ $$
Commented by mathdanisur last updated on 04/Jul/21
$${Si},\:{por}\:{favor} \\ $$