Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 197299 by bbbbbbbb last updated on 12/Sep/23

((−64))^(1/6) −((−10))^(1/(10)) =?  I need so much plz

$$\sqrt[{\mathrm{6}}]{−\mathrm{64}}−\sqrt[{\mathrm{10}}]{−\mathrm{10}}=? \\ $$$$\boldsymbol{{I}}\:\boldsymbol{\mathrm{need}}\:\boldsymbol{\mathrm{so}}\:\boldsymbol{\mathrm{much}}\:\boldsymbol{\mathrm{plz}} \\ $$

Answered by Frix last updated on 13/Sep/23

∀n∈N\{0}: −n=ne^(iπ)  ⇒  ((−n))^(1/k) =(n)^(1/k) e^(i(π/k)) =(n)^(1/k) (cos (π/k) +i sin (π/k))

$$\forall{n}\in\mathbb{N}\backslash\left\{\mathrm{0}\right\}:\:−{n}={n}\mathrm{e}^{\mathrm{i}\pi} \:\Rightarrow \\ $$$$\sqrt[{{k}}]{−{n}}=\sqrt[{{k}}]{{n}}\mathrm{e}^{\mathrm{i}\frac{\pi}{{k}}} =\sqrt[{{k}}]{{n}}\left(\mathrm{cos}\:\frac{\pi}{{k}}\:+\mathrm{i}\:\mathrm{sin}\:\frac{\pi}{{k}}\right) \\ $$

Terms of Service

Privacy Policy

Contact: [email protected]