Question Number 196398 by tri26112004 last updated on 24/Aug/23 | ||
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$${y}={f}\left({x}\right) \\ $$$${Give}:\:{xy}−{y}'={x}^{\mathrm{2}} \\ $$$${Find}\:{y}=¿ \\ $$ | ||
Commented by mr W last updated on 24/Aug/23 | ||
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$${d}.{e}.\:{of}\:{type}\:{y}'+{p}\left({x}\right){y}={q}\left({x}\right) \\ $$ | ||
Commented by mr W last updated on 25/Aug/23 | ||
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