Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 196070 by sniper237 last updated on 17/Aug/23

During an invasion   In the amazon dominion  Every evening , every  invader   kills  an  amazon warrior   Every morning , every amazon  kills   an invader soldier  The 8^(th)  day evening , there remains   only one amazon  and no invader    How many  were they in each part ?

$${During}\:{an}\:{invasion}\: \\ $$$${In}\:{the}\:{amazon}\:{dominion} \\ $$$${Every}\:{evening}\:,\:{every}\:\:{invader}\: \\ $$$${kills}\:\:{an}\:\:{amazon}\:{warrior}\: \\ $$$${Every}\:{morning}\:,\:{every}\:{amazon} \\ $$$${kills}\:\:\:{an}\:{invader}\:{soldier} \\ $$$${The}\:\mathrm{8}^{{th}} \:{day}\:{evening}\:,\:{there}\:{remains}\: \\ $$$${only}\:{one}\:{amazon}\:\:{and}\:{no}\:{invader} \\ $$$$ \\ $$$${How}\:{many}\:\:{were}\:{they}\:{in}\:{each}\:{part}\:? \\ $$

Answered by jabarsing last updated on 18/Aug/23

1597 amazon  987 invader

$$\mathrm{1597}\:{amazon} \\ $$$$\mathrm{987}\:{invader}\: \\ $$

Commented by sniper237 last updated on 18/Aug/23

That′s right    { ((x_(n+1)  = x_n −y_n )),((y_(n+1) = y_n −x_(n+1) )) :}and  x_8 =1 , y_8 =0  V_(n+1)  = AV_n      ⇒ V_8  = A^8 V_0     ((x_0 ),(y_0 ) )= (((1     −1)),((−1     2)) )^(−8)  ((x_8 ),(y_8 ) )

$${That}'{s}\:{right}\: \\ $$$$\begin{cases}{{x}_{{n}+\mathrm{1}} \:=\:{x}_{{n}} −{y}_{{n}} }\\{{y}_{{n}+\mathrm{1}} =\:{y}_{{n}} −{x}_{{n}+\mathrm{1}} }\end{cases}{and}\:\:{x}_{\mathrm{8}} =\mathrm{1}\:,\:{y}_{\mathrm{8}} =\mathrm{0} \\ $$$${V}_{{n}+\mathrm{1}} \:=\:{AV}_{{n}} \:\:\:\:\:\Rightarrow\:{V}_{\mathrm{8}} \:=\:{A}^{\mathrm{8}} {V}_{\mathrm{0}} \: \\ $$$$\begin{pmatrix}{{x}_{\mathrm{0}} }\\{{y}_{\mathrm{0}} }\end{pmatrix}=\begin{pmatrix}{\mathrm{1}\:\:\:\:\:−\mathrm{1}}\\{−\mathrm{1}\:\:\:\:\:\mathrm{2}}\end{pmatrix}^{−\mathrm{8}} \begin{pmatrix}{{x}_{\mathrm{8}} }\\{{y}_{\mathrm{8}} }\end{pmatrix}\: \\ $$

Terms of Service

Privacy Policy

Contact: [email protected]