Question Number 194089 by a.lgnaoui last updated on 27/Jun/23 | ||
$$\mathrm{Determiner}\:\mathrm{le}\:\mathrm{rayon}\:\boldsymbol{\mathrm{r}} \\ $$ | ||
Commented by a.lgnaoui last updated on 27/Jun/23 | ||
Commented by cherokeesay last updated on 27/Jun/23 | ||
Commented by a.lgnaoui last updated on 28/Jun/23 | ||
$$\mathrm{thanks}\: \\ $$ | ||
Answered by mr W last updated on 27/Jun/23 | ||
$$\mathrm{90}°+\alpha=\mathrm{135}° \\ $$$$\Rightarrow\alpha=\mathrm{45}° \\ $$$$\left(\sqrt{\mathrm{2}}{r}\right)^{\mathrm{2}} =\left(\mathrm{12}+\mathrm{2}\right)^{\mathrm{2}} +\mathrm{2}^{\mathrm{2}} \\ $$$$\Rightarrow{r}=\mathrm{10} \\ $$ | ||
Commented by mr W last updated on 27/Jun/23 | ||
Commented by a.lgnaoui last updated on 28/Jun/23 | ||
$$\mathrm{thanks} \\ $$ | ||