Question Number 190667 by 073 last updated on 08/Apr/23 | ||
Answered by manxsol last updated on 08/Apr/23 | ||
$${ABABAB}\:\mid\:{AB} \\ $$$$\underset{−} {{AB}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{10101} \\ $$$$\:\:\:\:\:\mathrm{0}{A}\boldsymbol{{B}} \\ $$$$\:\:\:\:\:\:\:\:\underset{−} {{AB}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{0}{A}\boldsymbol{{B}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{−} {{AB}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{0} \\ $$ | ||
Commented by manxsol last updated on 08/Apr/23 | ||
$${descomposicion}\:{polinomica} \\ $$$${ABABAB}=\overline {{AB}}×\mathrm{10000}+ \\ $$$$\overline {{AB}}×\mathrm{100}+\overline {{AB}}=\overline {{AB}}×\left(\mathrm{1000}+\mathrm{100}+\mathrm{1}\right) \\ $$$$={AB}×\mathrm{10101} \\ $$ | ||
Answered by mehdee42 last updated on 08/Apr/23 | ||
$$\mathrm{10101}\:\:{e}\:\checkmark \\ $$$${ababab}={ab}\left(\mathrm{10000}+\mathrm{100}+\mathrm{1}\right)=\mathrm{10101}{ab} \\ $$ | ||
Commented by 073 last updated on 08/Apr/23 | ||
$$\mathrm{how}\:\mathrm{to}\:\mathrm{find}\:\mathrm{10000},\mathrm{100},\mathrm{1}?? \\ $$ | ||