Question Number 188209 by Rupesh123 last updated on 26/Feb/23
Answered by Ezzat last updated on 26/Feb/23
$$\left(\mathrm{2}\:{R}\:{sinB}\:\right)^{\mathrm{2}} .{sin}^{\mathrm{2}} \left({A}\right)−\left(\:\mathrm{2}\:{R}\:{sinA}\right)^{\mathrm{2}} \:{sin}^{\mathrm{2}} {B}\:=\mathrm{48}\:−{a}^{\mathrm{2}} \\ $$$$\mathrm{4}\:{R}^{\mathrm{2}} \:{sin}^{\mathrm{2}} {B}\:.{sin}^{\mathrm{2}} {A}\:−\mathrm{4}{R}^{\mathrm{2}} {sin}^{\mathrm{2}} {A}\:.{sin}^{\mathrm{2}} {B}\:=\:\mathrm{48}\:−{a}^{\mathrm{2}} \\ $$$$\mathrm{0}\:=\:\mathrm{48}\:−{a}^{\mathrm{2}} \\ $$$${a}=\sqrt{\mathrm{48}}=\mathrm{4}\sqrt{\mathrm{3}} \\ $$
Commented by Rupesh123 last updated on 26/Feb/23
Perfect ��