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Question Number 181976 by mr W last updated on 02/Dec/22

Answered by HeferH last updated on 02/Dec/22

5?

$$\mathrm{5}? \\ $$

Commented by mr W last updated on 03/Dec/22

yes.

$${yes}. \\ $$

Answered by som(math1967) last updated on 03/Dec/22

x+y+7=1+y+2+7+2★ x=5 ★both side =(1/2)of rectangle

$${x}+{y}+\mathrm{7}=\mathrm{1}+{y}+\mathrm{2}+\mathrm{7}+\mathrm{2}\bigstar \\ $$$$\:{x}=\mathrm{5} \\ $$$$\bigstar{both}\:{side}\:=\frac{\mathrm{1}}{\mathrm{2}}{of}\:{rectangle} \\ $$

Commented by som(math1967) last updated on 03/Dec/22

Commented by mr W last updated on 03/Dec/22

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Commented by SEKRET last updated on 03/Dec/22

S=6+1+y+2+z+2+7+x=18+x+y+z (S/2)= 6+x+z S=12+2x+2z (S/2)=x+y+7 S=14+2x+2y 12+2x+2z=14+2x+2y z = y+2 18+x+y+z=12+2x+2z=14+2x+2y 6+y=x+z=x+y+2 4=x

$$\:\:\boldsymbol{\mathrm{S}}=\mathrm{6}+\mathrm{1}+\boldsymbol{\mathrm{y}}+\mathrm{2}+\boldsymbol{\mathrm{z}}+\mathrm{2}+\mathrm{7}+\boldsymbol{\mathrm{x}}=\mathrm{18}+\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{y}}+\boldsymbol{\mathrm{z}} \\ $$$$\:\:\frac{\boldsymbol{\mathrm{S}}}{\mathrm{2}}=\:\mathrm{6}+\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{z}}\:\:\:\:\boldsymbol{\mathrm{S}}=\mathrm{12}+\mathrm{2}\boldsymbol{\mathrm{x}}+\mathrm{2}\boldsymbol{\mathrm{z}} \\ $$$$\:\:\:\frac{\boldsymbol{\mathrm{S}}}{\mathrm{2}}=\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{y}}+\mathrm{7}\:\:\:\:\:\boldsymbol{\mathrm{S}}=\mathrm{14}+\mathrm{2}\boldsymbol{\mathrm{x}}+\mathrm{2}\boldsymbol{\mathrm{y}} \\ $$$$\:\:\:\:\:\mathrm{12}+\mathrm{2}\boldsymbol{\mathrm{x}}+\mathrm{2}\boldsymbol{\mathrm{z}}=\mathrm{14}+\mathrm{2}\boldsymbol{\mathrm{x}}+\mathrm{2}\boldsymbol{\mathrm{y}}\: \\ $$$$\:\:\:\:\:\:\:\boldsymbol{\mathrm{z}}\:=\:\boldsymbol{\mathrm{y}}+\mathrm{2}\:\:\:\:\:\: \\ $$$$\mathrm{18}+\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{y}}+\boldsymbol{\mathrm{z}}=\mathrm{12}+\mathrm{2}\boldsymbol{\mathrm{x}}+\mathrm{2}\boldsymbol{\mathrm{z}}=\mathrm{14}+\mathrm{2}\boldsymbol{\mathrm{x}}+\mathrm{2}\boldsymbol{\mathrm{y}} \\ $$$$\:\:\:\:\mathrm{6}+\boldsymbol{\mathrm{y}}=\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{z}}=\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{y}}+\mathrm{2}\:\: \\ $$$$\:\:\:\:\mathrm{4}=\boldsymbol{\mathrm{x}} \\ $$$$ \\ $$$$ \\ $$

Answered by SEKRET last updated on 03/Dec/22

4?

$$\:\:\mathrm{4}? \\ $$

Commented by mr W last updated on 03/Dec/22

no, x=5.

$${no},\:{x}=\mathrm{5}. \\ $$

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