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Question Number 181628 by Tawa11 last updated on 27/Nov/22

find the domain and range of   y  =  (1/((x  −  1)(x  +  2)))  restricted to   0  ≤  x  ≤  6

$$\mathrm{find}\:\mathrm{the}\:\mathrm{domain}\:\mathrm{and}\:\mathrm{range}\:\mathrm{of}\:\:\:\mathrm{y}\:\:=\:\:\frac{\mathrm{1}}{\left(\mathrm{x}\:\:−\:\:\mathrm{1}\right)\left(\mathrm{x}\:\:+\:\:\mathrm{2}\right)} \\ $$$$\mathrm{restricted}\:\mathrm{to}\:\:\:\mathrm{0}\:\:\leqslant\:\:\mathrm{x}\:\:\leqslant\:\:\mathrm{6} \\ $$

Answered by Acem last updated on 27/Nov/22

Commented by Acem last updated on 27/Nov/22

⊛ (1/0^( ±) )

$$\circledast\:\frac{\mathrm{1}}{\mathrm{0}^{\:\pm} } \\ $$

Commented by mr W last updated on 28/Nov/22

domain:  [0,6]−{1}  range:  (−∞,−(1/2)] ∩[(1/(40)),+∞)

$${domain}: \\ $$$$\left[\mathrm{0},\mathrm{6}\right]−\left\{\mathrm{1}\right\} \\ $$$${range}: \\ $$$$\left(−\infty,−\frac{\mathrm{1}}{\mathrm{2}}\right]\:\cap\left[\frac{\mathrm{1}}{\mathrm{40}},+\infty\right) \\ $$

Commented by Tawa11 last updated on 28/Nov/22

God bless you sirs.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sirs}. \\ $$

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