Question Number 176925 by Ar Brandon last updated on 28/Sep/22 | ||
Answered by mindispower last updated on 28/Sep/22 | ||
$$={x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{2}{xy}+{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{4} \\ $$$$\left({x}−{y}\right)^{\mathrm{2}} +\left({x}−\mathrm{2}\right)^{\mathrm{2}} =\mathrm{0} \\ $$$${x}={y}=\mathrm{2} \\ $$ | ||
Commented by Ar Brandon last updated on 28/Sep/22 | ||
Thanks, Sir! I stopped on the second line. | ||
Commented by mindispower last updated on 28/Sep/22 | ||
$${avec}\:{plaisir}\:{bonne}\:{journee} \\ $$ | ||
Commented by Ar Brandon last updated on 28/Sep/22 | ||
Merci monsieur ! Meilleure à vous✨ | ||