Question Number 171132 by cortano1 last updated on 08/Jun/22 | ||
Answered by kapoorshah last updated on 08/Jun/22 | ||
$${PA}\:=\:\left(−\mathrm{3},\:−\mathrm{4}\right)\: \\ $$$${PT}\:\:=\:\:\left(−\mathrm{1},\:−\mathrm{4}\right) \\ $$$$\mathrm{cos}\:\theta\:=\:\frac{{PA}\:.\:{PT}}{\mid{PA}\mid\:.\:\mid{PT}\mid} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:=\:\frac{\mathrm{3}\:+\:\mathrm{16}}{\mathrm{5}\:.\:\sqrt{\mathrm{17}}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:=\:\frac{\mathrm{19}}{\mathrm{5}\sqrt{\mathrm{17}}} \\ $$$$\mathrm{sin}\:\theta\:=\:\frac{\mathrm{8}}{\mathrm{5}\sqrt{\mathrm{17}}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:=\:\frac{\mathrm{8}\sqrt{\mathrm{17}}}{\mathrm{85}} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$ \\ $$ | ||
Commented by kapoorshah last updated on 08/Jun/22 | ||