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Question Number 168035 by pete last updated on 01/Apr/22 | ||
$$\mathrm{In}\:\mathrm{an}\:\mathrm{examination},\:\mathrm{the}\:\mathrm{probability}\:\mathrm{of}\:\mathrm{charles} \\ $$$$\mathrm{scoring}\:\mathrm{the}\:\mathrm{highest}\:\mathrm{mark}\:\mathrm{in}\:\mathrm{Maths},\:\mathrm{Physics} \\ $$$$\mathrm{and}\:\mathrm{Chemistry}\:\mathrm{are}\:\mathrm{0}.\mathrm{90},\:\mathrm{0}.\mathrm{75}\:\mathrm{and}\:\mathrm{0}.\mathrm{80}\:\mathrm{respectively}. \\ $$$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{he}\:\mathrm{will}\:\mathrm{get} \\ $$$$\mathrm{the}\:\mathrm{highest}\:\mathrm{mark}\:\mathrm{in}\:\mathrm{at}\:\mathrm{least}\:\mathrm{3}\:\mathrm{subjects}. \\ $$ | ||
Commented by MJS_new last updated on 01/Apr/22 | ||
$$``\mathrm{at}\:\mathrm{least}\:\mathrm{3}\:\mathrm{subjects}''\:\mathrm{with}\:\mathrm{3}\:\mathrm{subjects}\:\mathrm{given} \\ $$$$\mathrm{means}\:``\mathrm{in}\:\mathrm{all}\:\mathrm{3}\:\mathrm{subjects}''\:\Rightarrow \\ $$$$.\mathrm{9}×.\mathrm{75}×.\mathrm{8}=.\mathrm{54} \\ $$ | ||
Commented by pete last updated on 02/Apr/22 | ||
$$\mathrm{Thanks}\:\mathrm{Sir} \\ $$ | ||
Commented by pete last updated on 05/Apr/22 | ||
$$\mathrm{thanks}\:\mathrm{very}\:\mathrm{much} \\ $$ | ||