Question Number 166678 by Laters last updated on 24/Feb/22 | ||
$$\mathrm{4}+\boldsymbol{{x}}+\mathrm{2}\boldsymbol{{x}}=\mathrm{8}+\mathrm{2}\left(\mathrm{3}+\boldsymbol{{x}}\right)−\mathrm{3} \\ $$$$\boldsymbol{{F}}{ind}\:{x} \\ $$$$ \\ $$ | ||
Answered by nurtani last updated on 24/Feb/22 | ||
$$\mathrm{4}+{x}+\mathrm{2}{x}=\mathrm{8}+\mathrm{2}\left(\mathrm{3}+{x}\right)−\mathrm{3} \\ $$$$\Leftrightarrow\:\mathrm{4}+\mathrm{3}{x}=\mathrm{5}+\mathrm{6}+\mathrm{2}{x} \\ $$$$\Leftrightarrow\mathrm{3}{x}−\mathrm{2}{x}=\mathrm{11}−\mathrm{4} \\ $$$$\Leftrightarrow\:{x}\:=\:\mathrm{7} \\ $$$$\:\:\:\therefore\:\:{x}\:=\:\mathrm{7} \\ $$ | ||