Question Number 160188 by quvonnn last updated on 25/Nov/21 | ||
Commented by quvonnn last updated on 25/Nov/21 | ||
$$\boldsymbol{{x}}_{\mathrm{1}_{} } \centerdot\:\boldsymbol{{x}}_{\mathrm{2}} \:\centerdot\boldsymbol{{x}}_{\mathrm{3}} \centerdot\:...\centerdot\boldsymbol{{x}}_{\boldsymbol{{n}}} =\:?? \\ $$ | ||