Question Number 154100 by solihin last updated on 14/Sep/21 | ||
Answered by peter frank last updated on 14/Sep/21 | ||
$$\sqrt{\mathrm{a}}\:+\sqrt{\mathrm{b}}\:=\sqrt{\mathrm{c}} \\ $$$$\left(\sqrt{\mathrm{a}}\:+\sqrt{\mathrm{b}}\right)^{\mathrm{2}} =\left(\sqrt{\mathrm{c}}\:\right)^{\mathrm{2}} \\ $$$$\mathrm{a}+\mathrm{2}\sqrt{\mathrm{ab}}\:+\mathrm{b}=\mathrm{c} \\ $$$$\mathrm{5x}+\mathrm{1}+\mathrm{2}\sqrt{\left(\mathrm{5x}+\mathrm{1}\right)\left(\mathrm{x}−\mathrm{2}\right)}\:=\mathrm{8x}+\mathrm{1} \\ $$$$\left(\mathrm{2}\sqrt{\left(\mathrm{5x}+\mathrm{1}\right)\left(\mathrm{x}−\mathrm{2}\right)}\:=\mathrm{3x}\right. \\ $$$$\mathrm{4}\left[\left(\mathrm{5x}+\mathrm{1}\right)\left(\mathrm{x}−\mathrm{2}\right)\right]=\mathrm{9x}^{\mathrm{2}} \\ $$$$ \\ $$ | ||
Commented by Rasheed.Sindhi last updated on 14/Sep/21 | ||
$$\mathrm{5x}+\mathrm{1}+\mathrm{2}\sqrt{\left(\mathrm{5x}+\mathrm{1}\right)\left(\mathrm{x}−\mathrm{2}\right)}\:+\mathrm{x}−\mathrm{2}=\mathrm{8x}+\mathrm{1} \\ $$$$ \\ $$ | ||