Question Number 153438 by BHOOPENDRA last updated on 07/Sep/21
Commented by MJS_new last updated on 07/Sep/21
$$\mathrm{to}\:\mathrm{reach}\:\mathrm{maximum}\:\mathrm{height}\:\mathrm{putting}\:\mathrm{a}\:\mathrm{hemisphere} \\ $$$$\mathrm{on}\:\mathrm{one}\:\mathrm{with}\:{r}_{\mathrm{1}} =\mathrm{1}\:\mathrm{you}\:\mathrm{need}\:{r}_{\mathrm{2}} =\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}.\:\mathrm{this}\:\mathrm{should} \\ $$$$\mathrm{help}... \\ $$
Commented by BHOOPENDRA last updated on 07/Sep/21
$${can}\:{you}\:{elaborate}\:{more}? \\ $$