Question Number 152889 by SANOGO last updated on 02/Sep/21
$$\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{k}^{\alpha} }{\left({n}+\mathrm{1}\right)^{\alpha} \:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\left(\mathrm{1}+{n}\alpha\right)}=\frac{\mathrm{1}}{\mathrm{6}{o}}\: \\ $$$$\alpha=? \\ $$$$\alpha=?{q} \\ $$
Commented by mr W last updated on 02/Sep/21
$${i}\:{red}\:{flagged}\:{this}\:{and}\:{other}\:{posts}\:{of} \\ $$$${yours}. \\ $$
Commented by SANOGO last updated on 02/Sep/21
$${je}\:{ne}\:{comprend}\:{pas} \\ $$
Commented by puissant last updated on 03/Sep/21
$${comme}\:{ca}\:{affiche}\:{rouge}\:{en}\:{haut} \\ $$$${ca}\:{veut}\:{dire}\:{que}\:{tu}\:{as}\:{deja}\:{post}\acute {{e}}\:{ca} \\ $$$${plusieurs}\:{fois}.. \\ $$
Commented by talminator2856791 last updated on 03/Sep/21
$$\:\mathrm{we}\:\mathrm{know} \\ $$
Commented by mr W last updated on 04/Sep/21
$${i}\:{red}\:{flagged}\:{this}\:{post}\:{because}\:{you} \\ $$$${used}\:{different}\:{font}\:{sizes}\:{and}\:{the} \\ $$$${post}\:{is}\:{badly}\:{readable}. \\ $$
Commented by mr W last updated on 04/Sep/21
Commented by mr W last updated on 04/Sep/21
$${try}\:{to}\:{set}\:{the}\:{defaut}\:{font}\:{size}\:\mathrm{20}. \\ $$$${try}\:{to}\:{avoid}\:{using}\:{extremly}\:{large}\:{or} \\ $$$${extremly}\:{small}\:{fonts}! \\ $$