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Question Number 148339 by mathdanisur last updated on 27/Jul/21

arccos (cos 9) = ?

$${arccos}\:\left({cos}\:\mathrm{9}\right)\:=\:? \\ $$

Answered by Olaf_Thorendsen last updated on 27/Jul/21

x = arccos(cos9))  x = arccos(cos(9−2π))), 9−2π ∈[0,π]  x = 9−2π

$$\left.{x}\:=\:\mathrm{arccos}\left(\mathrm{cos9}\right)\right) \\ $$$$\left.{x}\:=\:\mathrm{arccos}\left(\mathrm{cos}\left(\mathrm{9}−\mathrm{2}\pi\right)\right)\right),\:\mathrm{9}−\mathrm{2}\pi\:\in\left[\mathrm{0},\pi\right] \\ $$$${x}\:=\:\mathrm{9}−\mathrm{2}\pi \\ $$

Commented by mathdanisur last updated on 27/Jul/21

Thank you Sir

$${Thank}\:{you}\:{Sir} \\ $$

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