Question Number 147229 by Tawa11 last updated on 19/Jul/21
Answered by Olaf_Thorendsen last updated on 19/Jul/21
$$\mathrm{2}×\left(\mathrm{42}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{4}}×\pi×\mathrm{42}^{\mathrm{2}} \right)\:=\:\mathrm{882}\left(\mathrm{4}−\pi\right) \\ $$
Commented by Tawa11 last updated on 19/Jul/21
$$\mathrm{Thanks}\:\mathrm{sir},\:\mathrm{i}\:\mathrm{appreciate}. \\ $$
Answered by nimnim last updated on 19/Jul/21
$${a}=\mathrm{42}\Rightarrow{r}=\mathrm{21}\sqrt{\mathrm{2}} \\ $$$${Area}\:{of}\:{shaded}\:{region}=\mathrm{2}\left({a}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{4}}\pi{r}^{\mathrm{2}} \right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{2}×\mathrm{42}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{22}}{\mathrm{7}}×\mathrm{21}\sqrt{\mathrm{2}}×\mathrm{21}\sqrt{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{3528}−\mathrm{1386}=\mathrm{2142}\:{cm}^{\mathrm{2}} . \\ $$
Commented by Rasheed.Sindhi last updated on 19/Jul/21
$${a}={r}=\mathrm{42} \\ $$
Commented by nimnim last updated on 19/Jul/21
$${sorry},\:{I}\:{miscalculated}.. \\ $$