Question Number 139824 by mathsuji last updated on 01/May/21
$${Solve}\:{in}\:\mathbb{R}\:{the}\:{following}\:{equation}: \\ $$$$\mathrm{2}\centerdot\mathrm{3}^{{x}} +\mathrm{5}\centerdot\mathrm{4}^{{x}} =\mathrm{4}\centerdot\mathrm{5}^{{x}} +\mathrm{3}\centerdot\mathrm{2}^{{x}} \\ $$
Answered by MJS_new last updated on 02/May/21
$$\mathrm{obviously}\:{x}=\mathrm{0}\vee{x}=\mathrm{1} \\ $$
Commented by MJS_new last updated on 02/May/21
$$\mathrm{no}\:\mathrm{exact}\:\mathrm{solution}\:\mathrm{method} \\ $$
Commented by mathsuji last updated on 02/May/21
$${solutions}\:{sir}\:{pliz} \\ $$
Commented by mathsuji last updated on 02/May/21
$${thanks}\:{sir} \\ $$