Question Number 138059 by sahnaz last updated on 09/Apr/21 | ||
$$\frac{\mathrm{2}^{\mathrm{n}+\mathrm{1}} +\:\mathrm{3}^{\mathrm{n}+\mathrm{2}} +\:\mathrm{4}^{\mathrm{n}+\mathrm{3}} }{\mathrm{2}^{\mathrm{n}} +\mathrm{3}^{\mathrm{n}} +\mathrm{4}^{\mathrm{n}} }=? \\ $$ | ||
Answered by MJS_new last updated on 10/Apr/21 | ||
$$\mathrm{9}+\frac{\mathrm{2}^{{n}} \left(\mathrm{55}×\mathrm{2}^{{n}} −\mathrm{7}\right)}{\mathrm{3}^{{n}} +\mathrm{2}^{{n}} \left(\mathrm{2}^{{n}} +\mathrm{1}\right)} \\ $$$$\underset{{n}\rightarrow−\infty} {\mathrm{lim}}\:=\mathrm{2} \\ $$$$\underset{{n}\rightarrow+\infty} {\mathrm{lim}}\:=\mathrm{64} \\ $$ | ||