Question Number 136760 by I want to learn more last updated on 25/Mar/21
Answered by mr W last updated on 25/Mar/21
$$\frac{{BC}}{\mathrm{sin}\:\angle{BDC}}=\frac{{CD}}{\mathrm{sin}\:\mathrm{30}°}\:\:\:\:\:...\left({i}\right) \\ $$$$\frac{\mathrm{sin}\:\angle{BDA}}{{AB}}=\frac{\mathrm{sin}\:\mathrm{45}°}{{DA}}\:\:\:...\left({ii}\right) \\ $$$$\left({i}\right)×\left({ii}\right): \\ $$$$\frac{{BC}}{{AB}}=\frac{\mathrm{sin}\:\mathrm{45}°}{\mathrm{sin}\:\mathrm{30}°}=\sqrt{\mathrm{2}} \\ $$
Commented by I want to learn more last updated on 25/Mar/21
$$\mathrm{I}\:\mathrm{appreciate}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you} \\ $$
Commented by [email protected] last updated on 27/Mar/21
$$\mathrm{thanks} \\ $$