Question Number 133601 by help last updated on 23/Feb/21 | ||
Answered by benjo_mathlover last updated on 23/Feb/21 | ||
$$\:\frac{\mathrm{sin}^{\mathrm{2}} \:\theta}{\mathrm{sin}\:\theta−\mathrm{cos}\:\theta}\:+\:\frac{\mathrm{cos}\:^{\mathrm{2}} \theta}{\mathrm{cos}\:\theta−\mathrm{sin}\:\theta}\:= \\ $$$$\:\frac{\mathrm{cos}\:^{\mathrm{2}} \theta−\mathrm{sin}\:^{\mathrm{2}} \theta}{\mathrm{cos}\:\theta−\mathrm{sin}\:\theta}\:=\:\mathrm{cos}\:\theta+\mathrm{sin}\:\theta \\ $$ | ||