Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 13349 by tawa tawa last updated on 19/May/17

Answered by ajfour last updated on 19/May/17

for x≠(2/a) ,we have  24x^2 +25x−47=−(ax−2)(8x+3)−53  24x^2 +25x−47=−8ax^2 +(16−3a)x+6−53  comparing coefficients of x^2    or x we see   a=−3  answer is   B)  −3   .

$${for}\:{x}\neq\frac{\mathrm{2}}{{a}}\:,{we}\:{have} \\ $$$$\mathrm{24}{x}^{\mathrm{2}} +\mathrm{25}{x}−\mathrm{47}=−\left({ax}−\mathrm{2}\right)\left(\mathrm{8}{x}+\mathrm{3}\right)−\mathrm{53} \\ $$$$\mathrm{24}{x}^{\mathrm{2}} +\mathrm{25}{x}−\mathrm{47}=−\mathrm{8}{ax}^{\mathrm{2}} +\left(\mathrm{16}−\mathrm{3}{a}\right){x}+\mathrm{6}−\mathrm{53} \\ $$$${comparing}\:{coefficients}\:{of}\:{x}^{\mathrm{2}} \: \\ $$$${or}\:{x}\:{we}\:{see}\:\:\:\boldsymbol{{a}}=−\mathrm{3} \\ $$$$\left.{answer}\:{is}\:\:\:{B}\right)\:\:−\mathrm{3}\:\:\:. \\ $$

Commented by tawa tawa last updated on 19/May/17

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com