Question Number 129801 by bramlexs22 last updated on 19/Jan/21 | ||
$$\:\mathrm{cot}\:\mathrm{15}°\:\mathrm{cot}\:\mathrm{16}°\:\mathrm{cot}\:\mathrm{17}°...\:\mathrm{cot}\:\mathrm{75}°= \\ $$ | ||
Answered by EDWIN88 last updated on 19/Jan/21 | ||
$$=\mathrm{1} \\ $$$$\:\left[\:\mathrm{cot}\:\mathrm{15}°=\mathrm{tan}\:\mathrm{75}°\:\mathrm{etc}\:\right]\: \\ $$ | ||