Question Number 128874 by help last updated on 11/Jan/21 | ||
Commented by Ritu Jain last updated on 11/Jan/21 | ||
$$\mathrm{18} \\ $$ | ||
Answered by Olaf last updated on 11/Jan/21 | ||
$$\mathrm{16} \\ $$$$\mathrm{Sorry}\:\mathrm{18}\:\mathrm{sir}. \\ $$ | ||
Commented by help last updated on 11/Jan/21 | ||
how? | ||
Commented by mr W last updated on 11/Jan/21 | ||
$${C}_{\mathrm{2}} ^{\mathrm{4}} ×{C}_{\mathrm{1}} ^{\mathrm{3}} =\frac{\mathrm{4}×\mathrm{3}}{\mathrm{2}}×\mathrm{3}=\mathrm{18} \\ $$ | ||