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Question Number 128072 by benjo_mathlover last updated on 04/Jan/21
$$\:\frac{\mathrm{dy}}{\mathrm{dx}}\:+\:\mathrm{y}.\mathrm{sin}\:\mathrm{x}\:=\:\mathrm{y}^{\mathrm{2}} .\mathrm{sin}\:\mathrm{2x} \\ $$
Answered by bemath last updated on 04/Jan/21
