Question Number 126646 by sdfg last updated on 22/Dec/20 | ||
Commented by sdfg last updated on 22/Dec/20 | ||
$${please}\:{help} \\ $$ | ||
Answered by physicstutes last updated on 22/Dec/20 | ||
$${x}\left({t}\right)\:=\:{a}\:\mathrm{cos}\:\omega{t}\:\mathrm{and}\:{x}\left({t}\right)\:=\:{b}\:\mathrm{cos}\:\omega{t} \\ $$$$\mathrm{really}\:\mathrm{don}'\mathrm{t}\:\mathrm{hold}\:\mathrm{as}\:\mathrm{the}\:\mathrm{parametric}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{an}\:\mathrm{ellipse} \\ $$ | ||