Question Number 125858 by bramlexs22 last updated on 14/Dec/20
Commented by mr W last updated on 14/Dec/20
$$\mathrm{13}×\mathrm{26}×\mathrm{2}×\mathrm{62}.\mathrm{4}×\mathrm{1}=\mathrm{42}\:\mathrm{182}\:{ft}−{lb} \\ $$
Commented by bramlexs22 last updated on 14/Dec/20
$${sir}\:{how}\:{with}\:{integral}\:{method}? \\ $$
Commented by mr W last updated on 14/Dec/20
$${dW}=\rho{Ahdh} \\ $$$${W}=\rho{A}\int_{\mathrm{0}} ^{{H}} {hdh}=\frac{\rho{AH}^{\mathrm{2}} }{\mathrm{2}}=\rho{V}\frac{{H}}{\mathrm{2}} \\ $$$$=\mathrm{62}.\mathrm{4}×\mathrm{13}×\mathrm{26}×\mathrm{2}×\frac{\mathrm{2}}{\mathrm{2}}=\mathrm{42}\:\mathrm{182}\:{ft}−{lb} \\ $$
Commented by bramlexs22 last updated on 14/Dec/20
$${thank}\:{you}\:{sir} \\ $$