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Question Number 124681 by mathocean1 last updated on 05/Dec/20

solve in Z^2     (E): 3x−y=4

$${solve}\:{in}\:\mathbb{Z}^{\mathrm{2}} \:\: \\ $$$$\left({E}\right):\:\mathrm{3}{x}−{y}=\mathrm{4} \\ $$

Answered by Ar Brandon last updated on 05/Dec/20

(x,y)=(2,2)

$$\left(\mathrm{x},\mathrm{y}\right)=\left(\mathrm{2},\mathrm{2}\right) \\ $$

Answered by MJS_new last updated on 05/Dec/20

∀n∈Z: x=n∧y=3n−4

$$\forall{n}\in\mathbb{Z}:\:{x}={n}\wedge{y}=\mathrm{3}{n}−\mathrm{4} \\ $$

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