Question Number 119524 by help last updated on 25/Oct/20 | ||
Answered by benjo_mathlover last updated on 25/Oct/20 | ||
$${g}\left({x}\right)\:=\:\sqrt{\left(−\mathrm{1}\right)\left({x}−\mathrm{14}\right)}\:=\:\sqrt{{x}−\mathrm{14}}\:{i}\: \\ $$$${thus}\:{f}\left({x}\right)=\sqrt{{x}−\mathrm{14}}\:+\:{i}\:\sqrt{{x}−\mathrm{14}}\:=\:\left({i}+\mathrm{1}\right)\sqrt{{x}−\mathrm{14}} \\ $$ | ||