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Question Number 119114 by Hassen_Timol last updated on 22/Oct/20

Commented by Hassen_Timol last updated on 22/Oct/20

Could you please help me... I don't understand at all

Commented by MJS_new last updated on 22/Oct/20

T is not defined because k is an index with  1≤k≤p ⇒ we cannot compare S and T  please check the question.

$${T}\:\mathrm{is}\:\mathrm{not}\:\mathrm{defined}\:\mathrm{because}\:{k}\:\mathrm{is}\:\mathrm{an}\:\mathrm{index}\:\mathrm{with} \\ $$$$\mathrm{1}\leqslant{k}\leqslant{p}\:\Rightarrow\:\mathrm{we}\:\mathrm{cannot}\:\mathrm{compare}\:{S}\:\mathrm{and}\:{T} \\ $$$$\mathrm{please}\:\mathrm{check}\:\mathrm{the}\:\mathrm{question}. \\ $$

Commented by Hassen_Timol last updated on 22/Oct/20

Yes sorry, I posted the question corrected

Commented by MJS_new last updated on 22/Oct/20

ok

$$\mathrm{ok} \\ $$

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