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Question Number 115869 by bobhans last updated on 29/Sep/20
$$\:\frac{{dy}}{{dx}}\:+\mathrm{2}{y}\:=\:{x}^{\mathrm{3}} .{e}^{−\mathrm{2}{y}} \\ $$
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Previous in Differential Equation Next in Differential Equation | ||
Question Number 115869 by bobhans last updated on 29/Sep/20 | ||
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$$\:\frac{{dy}}{{dx}}\:+\mathrm{2}{y}\:=\:{x}^{\mathrm{3}} .{e}^{−\mathrm{2}{y}} \\ $$ | ||