Question Number 114482 by mohammad17 last updated on 19/Sep/20 | ||
Answered by 1549442205PVT last updated on 19/Sep/20 | ||
$$\left.\mathrm{Choose}\:\mathrm{ii}\right)−\mathrm{2},\mathrm{3},\mathrm{1}\:\mathrm{since} \\ $$$$\mathrm{x}^{\mathrm{3}} −\mathrm{2x}^{\mathrm{2}} −\mathrm{5x}+\mathrm{6}=\mathrm{0} \\ $$$$\Leftrightarrow\left(\mathrm{x}+\mathrm{2}\right)\left(\mathrm{x}−\mathrm{1}\right)\left(\mathrm{x}−\mathrm{3}\right)=\mathrm{0} \\ $$$$\Leftrightarrow\mathrm{x}\in\left\{−\mathrm{2};\mathrm{1};\mathrm{3}\right\} \\ $$ | ||
Commented by mohammad17 last updated on 19/Sep/20 | ||
$${thank}\:{you}\:{sir} \\ $$ | ||