Question Number 11408 by anisa last updated on 24/Mar/17
Answered by sm3l2996 last updated on 24/Mar/17
$$=\frac{\mathrm{sin}\left(\frac{\mathrm{4}\pi}{\mathrm{3}}\right)+\mathrm{cos}\left(\frac{\mathrm{4}\pi}{\mathrm{3}}\right)}{\mathrm{tg}\left(\frac{\mathrm{4}\pi}{\mathrm{3}}\right)}=\frac{\frac{−\sqrt{\mathrm{3}}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{2}}}{\sqrt{\mathrm{3}}} \\ $$$$=−\frac{\sqrt{\mathrm{3}}+\mathrm{1}}{\mathrm{2}\sqrt{\mathrm{3}}} \\ $$