Question Number 109746 by Joel574 last updated on 25/Aug/20 | ||
$$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\underset{{n}\:=\:\mathrm{0}} {\overset{\mathrm{2020}} {\sum}}\:\left[\frac{\mathrm{2}^{{n}} }{\mathrm{1}\:+\:\mathrm{3}^{\left(\mathrm{2}^{{n}} \right)} }\right] \\ $$ | ||
Commented by Her_Majesty last updated on 25/Aug/20 | ||
$$\approx.\mathrm{25} \\ $$ | ||
Commented by Joel574 last updated on 25/Aug/20 | ||
$$\mathrm{How}? \\ $$ | ||
Commented by Her_Majesty last updated on 25/Aug/20 | ||
$${sorry},\:{I}\:{misread}\:\mathrm{1}\leqslant{n}\:{instead}\:{of}\:\mathrm{0}\leqslant{n} \\ $$$${it}'{s}\:\approx.\mathrm{5} \\ $$ | ||