Question Number 10760 by Saham last updated on 24/Feb/17 | ||
$$\mathrm{A}\:\mathrm{block}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{2}.\mathrm{0kg}\:\mathrm{resting}\:\mathrm{on}\:\mathrm{a}\:\mathrm{smooth}\:\mathrm{horizontal}\:\mathrm{plane}\:\mathrm{is}\:\mathrm{acted} \\ $$$$\mathrm{upon}\:\mathrm{simultaneously}\:\mathrm{by}\:\mathrm{two}\:\mathrm{forces}\:\mathrm{10N}\:\mathrm{due}\:\mathrm{north}\:\mathrm{and}\:\mathrm{10N}\:\mathrm{due}\:\mathrm{east}. \\ $$$$\mathrm{The}\:\mathrm{magnitude}\:\mathrm{of}\:\mathrm{the}\:\mathrm{acceleration}\:\mathrm{produce}\:\mathrm{by}\:\mathrm{the}\:\mathrm{force}\:\mathrm{on}\:\mathrm{the}\:\mathrm{block}. \\ $$ | ||
Commented by chux last updated on 24/Feb/17 | ||
$$\mathrm{please}\:\mathrm{are}\:\mathrm{you}\:\mathrm{a}\:\mathrm{nigerian} \\ $$ | ||
Answered by mrW1 last updated on 24/Feb/17 | ||
$${total}\:{force}\:{F}=\sqrt{\mathrm{10}^{\mathrm{2}} +\mathrm{10}^{\mathrm{2}} }=\mathrm{14}.\mathrm{1}\:{N} \\ $$$${a}=\frac{{F}}{{m}}=\frac{\mathrm{14}.\mathrm{1}}{\mathrm{2}}=\mathrm{7}.\mathrm{05}\:{m}/{s}^{\mathrm{2}} \\ $$ | ||
Commented by Saham last updated on 24/Feb/17 | ||
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$ | ||