Question Number 106997 by Dwaipayan Shikari last updated on 08/Aug/20 | ||
Commented by mr W last updated on 08/Aug/20 | ||
$${mv}−{m}×\frac{−{v}}{\mathrm{2}}=\int_{\mathrm{0}} ^{{T}} {fdt}={FT} \\ $$$$\Rightarrow{F}=\frac{\mathrm{3}{mv}}{\mathrm{2}{T}} \\ $$ | ||
Commented by Dwaipayan Shikari last updated on 08/Aug/20 | ||
$$\mathrm{P}_{\mathrm{f}} −\mathrm{P}_{\mathrm{i}} =\int\mathrm{Fdt} \\ $$$$\mid−\frac{\mathrm{mv}}{\mathrm{2}}−\mathrm{mv}\mid=\mathrm{FT} \\ $$$$\mathrm{F}=\frac{\mathrm{3mv}}{\mathrm{2T}} \\ $$ | ||
Commented by mr W last updated on 08/Aug/20 | ||
$${you}\:{are}\:{right}\:{sir}!\:{i}\:{forgot}\:{the}\:``−''\:{sign}. \\ $$ | ||