Question Number 106921 by aurpeyz last updated on 07/Aug/20 | ||
Commented by aurpeyz last updated on 07/Aug/20 | ||
$${i}\:{didnt}\:{get}\:{the}\:{answer}\:{to}\:{the}\:{last}\:{part}.\:{pls} \\ $$$${help} \\ $$ | ||
Answered by mr W last updated on 07/Aug/20 | ||
$${uniform}\:{slow}\:{down}\:{means}\: \\ $$$${constant}\:{acceleration} \\ $$$${U}=\frac{\mathrm{8}×\mathrm{14}}{\mathrm{2}}=\mathrm{56}\:{rev} \\ $$$${s}=\mathrm{56}×\mathrm{2}\pi{r}=\mathrm{56}×\mathrm{2}\pi×\mathrm{0}.\mathrm{3}=\mathrm{105}.\mathrm{6}{m} \\ $$ | ||
Commented by aurpeyz last updated on 07/Aug/20 | ||
$${thank}\:{you}\:{Sir} \\ $$ | ||