Question Number 102507 by Study last updated on 09/Jul/20
$${li}\underset{{x}\rightarrow{e}^{{lnx}} } {{m}}\left(\frac{{x}}{{e}^{{lnx}} }\right)^{−{logx}} =? \\ $$
Commented by Study last updated on 09/Jul/20
$${help}\:{me} \\ $$
Commented by Dwaipayan Shikari last updated on 09/Jul/20
$$\mathrm{1}\:\:\:\left\{{x}\:{can}\:{take}\:{any}\:{value}\right\} \\ $$