Question Number 148994 by gsk2684 last updated on 02/Aug/21 | ||
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$$\left(\mathrm{102}\right)^{\mathrm{4}} \\ $$$${easy}\:{way}\:{to}\:{caculate} \\ $$ | ||
Answered by iloveisrael last updated on 02/Aug/21 | ||
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$$\left(\mathrm{100}+\mathrm{2}\right)^{\mathrm{4}} =\underset{\mathrm{n}=\mathrm{0}} {\overset{\mathrm{4}} {\sum}}\mathrm{C}_{\mathrm{k}} ^{\mathrm{4}} \left(\mathrm{100}\right)^{\mathrm{4}−\mathrm{k}} \:\left(\mathrm{2}\right)^{\mathrm{k}} \: \\ $$ | ||
Commented by gsk2684 last updated on 02/Aug/21 | ||
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$${thank}\:{u} \\ $$$${i}\:{did}\:{not}\:{remember}\: \\ $$ | ||