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Question Number 101110 by bemath last updated on 30/Jun/20

Answered by bramlex last updated on 30/Jun/20

v_(simon)  = 3×v_(Ian)   ⇒((6×50)/v_(Ian) ) = ((5(100+2x))/(3×v_(Ian) ))  180 = 100+2x ⇒x = 40 m ←wide is the pool

$${v}_{{simon}} \:=\:\mathrm{3}×{v}_{{Ian}} \\ $$$$\Rightarrow\frac{\mathrm{6}×\mathrm{50}}{{v}_{{Ian}} }\:=\:\frac{\mathrm{5}\left(\mathrm{100}+\mathrm{2}{x}\right)}{\mathrm{3}×{v}_{{Ian}} } \\ $$$$\mathrm{180}\:=\:\mathrm{100}+\mathrm{2}{x}\:\Rightarrow{x}\:=\:\mathrm{40}\:{m}\:\leftarrow{wide}\:{is}\:{the}\:{pool} \\ $$

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