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Question Number 25171 by NECx last updated on 05/Dec/17

100n>n^2  for integral n>100

$$\mathrm{100}{n}>{n}^{\mathrm{2}} \:{for}\:{integral}\:{n}>\mathrm{100} \\ $$$$ \\ $$

Answered by ajfour last updated on 05/Dec/17

n > 100  n=n  ⇒ n^2 >100n

$${n}\:>\:\mathrm{100} \\ $$$${n}={n} \\ $$$$\Rightarrow\:{n}^{\mathrm{2}} >\mathrm{100}{n} \\ $$

Commented by NECx last updated on 06/Dec/17

this is clear .Thanks

$${this}\:{is}\:{clear}\:.{Thanks} \\ $$

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